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Continuity Test
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Calculus 1
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Limits and
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Mathematics N5 Limits and
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0:43
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Shivang Maths Academy
Q) If 2cos^(β1) π₯ = π¦,then(A) 0β€π¦β€π(B) βπβ€π¦β€π(C) 0β€π¦β€2π(D) βπβ€π² β€ 0 #shivangmathsacademy
CBSE PYQ 2026 π± Most Students Get This WRONG | Inverse Trigonometry Trick π₯ Q) If 2cos^(β1) π₯=π¦, then (A) 0β€π¦β€π (B) βπβ€π¦β€π (C) 0β€π¦β€2π (D) βπβ€π² β€ 0 #class12maths #shivangmathsacademy #cbsemaths #class12th class 12th maths chapter number 2 inverse trigonometric functions class 12 class ...
1.5K views
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Continuity Test Tutorial
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Draw the graph of π(π₯)=π ππ^(β1) π₯, π₯β[β1/β2, 1/β2]. Also, write range of f(x). #trigonometry
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Q) If π ππ πππ‘^(β1) (π₯+1)]=πππ (tan^(β1) π₯), π‘βππ ππππ π₯.#class12maths #shivang
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Q) Simplify : tan^(β1) {β((1βcosπ₯)/(1+cosπ₯))}}#class12maths #shivangmathsacademy #cbsemaths
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Q) The value of tan[1/2 cos^(β1) (β5/3)] is (a) (3+β5)/2 (b) (3ββ5)/2(c) (β3+βg5)/2(d) (β3ββ5)/2
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Q) Simplify : tan^(β1) ((cos2π₯βsin2π₯)/(cos2π₯+sin2π₯)),0=π₯=π/4..#class12maths #shivangmathsaca
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Q) The function π defined by π(π₯)={ (π₯,f π₯β€1 5, if π₯= 1 is not continuous at(A) x=0(B) π₯
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Find k so that π(π₯)={((π₯^2β2π₯β3)/(π₯+1), π₯β β1 π, π₯=β1) is continuous at x=β1.#cbse2027 #maths
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Q) Check whether function f(x) defined as f(π₯)={((|π₯β3|)/(2(π₯β3)), π₯=3 (π₯β6)/6,π₯β₯3) Is
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Q) The function π defined by π(π₯)={ (π₯,f π₯β€1 5, if π₯= 1 is not continuous at(A) x=0(B) π₯
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Find k so that π(π₯)={((π₯^2β2π₯β3)/(π₯+1), π₯β β1 π, π₯=β1) is continuous at x=β1.#cbse2027 #maths
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Q) If π(π₯)={(3π₯β2, 0β€π₯β€1 2π₯^2+ππ₯, 1β€π₯β€2) is continuous for π₯β(0,2), then a is equal to
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Q) If π(π₯)={ ((π₯^2β4π₯β5)/(π₯+1), π₯β β1 π,&π₯=β1 is continuous at π₯=β1, then the value of π i
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If π(π₯)={ ((sin^2 ππ₯)/π₯^2 if π₯β 0 1 , if π₯=0) is continuous at π₯=0, then the value of ' π β
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Q) Find the value of π, so that π(π₯)={(πcosπ₯/(πβ2π₯), if π₯β π/2@3, if π₯=π/2) is continu
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Q) Domain of π ππ^(β1) (2π₯^2β3) is (A) (β1,0)βͺ(1,β2)(B) (ββ2,β1)βͺ(0,1)(C) [ββ2,β1]βͺ[1,β2](D) (β
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Q) If π(π₯)={((1βsin^3 π₯)/(3cos^2 π₯), for π₯β π/2 π, for π₯=π/2) is continuous at π₯=π/2, t
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